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  • Ratio of intensities between a point A and that of central fringe is 0.853 . Then path difference between two waves at point A will beOption: 1</strong

Ratio of intensities between a point A and that of central fringe is 0.853 . Then path difference between two waves at point A will be

Option: 1

\frac{\lambda}{2}


Option: 2

\frac{\lambda}{4}


Option: 3

\frac{\lambda}{8}


Option: 4

\lambda


Answers (1)

best_answer

\mathrm{\begin{aligned} & R^2=a^2+b^2+2 a b \cos \phi \\\\ & \frac{I_R}{I_{\text {max. }}}=0.853 \\\\ & \therefore I_R=0.853 I_{\text {max. }}=0.853 \times 4 I \\\\ & I_R=I+I_0+2 I \cos \phi=2 I(1+\cos \phi)=0.853 \times 4 I \\\\ & \Rightarrow \phi=\frac{\pi}{4}=\frac{\lambda}{8} \end{aligned}}

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