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If p\left ( A \right ) =0.4,\: P\left ( B \right )=0.8\: P\left ( \frac{B}{A} \right )=0.6\: then P\left ( A\cup B \right ) =

  • Option 1)

    0.24

  • Option 2)

    0.3

  • Option 3)

    0.48

  • Option 4)

    0.96

 

Answers (1)

best_answer

 

Conditional Probability -

 

P\left ( \frac{A}{B} \right )= \frac{P\left ( A\cap B \right )}{P\left ( B \right )}

and

P\left ( \frac{B}{A} \right )= \frac{P\left ( A\cap B \right )}{P\left ( A \right )}

 

- wherein

where P\left ( \frac{A}{B} \right ) probability of A when B already happened.

 

 P(\frac{B}{A})=\frac{P(A\cap B)}{P(A)}

0.6 =\frac{P(A\cap B)}{0.4}

{P(A\cap B)} = 0.24

{P(A\cap B)} = P(A) +P(B)- P(A\cap B)

= 0.4+ 0.8 -0.24

= 1.2 -0.24 = 0.96


Option 1)

0.24

Incorrect

Option 2)

0.3

Incorrect

Option 3)

0.48

Incorrect

Option 4)

0.96

Correct

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Plabita

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