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The elevation in boiling point for $1$ molal solution of non-volatile solute $\mathrm{A}$ is $\mathrm{3\; K}.$ The depression in freezing point for $2$ molal solution of $\mathrm{A}$ in the same solvent is $\mathrm{6\; K}.$ The ratio of $\mathrm{\mathrm{K}_{\mathrm{b}}}$ and $\mathrm{\mathrm{K}_{\mathrm{f}} \text { i.e., } \mathrm{K}_{\mathrm{b}} / \mathrm{K}_{\mathrm{f}}}$ is $\mathrm{\text { 1: } \mathrm{X}}$ . The value of $\mathrm{ \mathrm{X}}$ is [nearest integer]
Option: 1
1

Option: 2
-

Option: 3
-

Option: 4
-

Answers (1)

best_answer

We know,

$\mathrm{\Delta T_b=K_b m \text { and } \Delta T_f=K_f m}$

Now,

$\mathrm{\Delta T_{b}=3=K_{b}m=K_{b}\times1}$

$\mathrm{K_{b}=3}$

And

$\mathrm{\Delta T_{f}=6=K_{f}\times2}$

$\mathrm{K_{f}=3}$

So, the ratio of $\mathrm{K_{b}}$ and $\mathrm{K_{f}}$

$\mathrm{\frac{k_b}{k_f}=\frac{3}{3} \Rightarrow \frac{1}{x}=\frac{1}{1}}$

So, $\mathrm{x=1}$

Answer = 1

Posted by

shivangi.bhatnagar

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