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  • The elevation of boiling point of 0.1 m aq solution is two times that of 0.05 aq. <img alt="CaCl_{2}" src="http://entr

The elevation of boiling point of 0.1 m aq CrCl_{3}.xNH_{3} solution is two times that of 0.05 aq. CaCl_{2}  solution. The value of x _____ (Assume 100% ionization of complex and CaCl_{2} , coordination number of Cr is 6 and that all of NH_{3} molecules are present inside the coordination sphere.)
 

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\mathrm{\Delta T_{b}\; of \;CrCl_{3}.xNH_{3}= 2(\Delta T_{b}\; of \; CaCl_{2})}

i \times 0.1 = 2 \times 3 \times 0.05

Thus, i = 3

Therefore, the complex is dissociated into 3 ions.

Hence, complex is [Cr(NH_{3})_{5}Cl]Cl_{2}

Thus, the value is 5.

Posted by

Kuldeep Maurya

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