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  • The height of any point above the surface of earth is equal to diameter of earth. The value of acceleration due to gravity at

The height of any point P above the surface of earth is equal to diameter of earth. The value of acceleration due to gravity at point P will be : (Given g = acceleration due to gravity at the surface of earth).
 

Option: 1

\mathrm{g} / 2


Option: 2

\mathrm{g} / 4


Option: 3

\mathrm{g} / 3


Option: 4

\mathrm{g} / 9


Answers (1)

best_answer

At \mathrm{h= R},
\mathrm{g_{h}= \frac{gR^{2}}{\left ( R+h \right )^{2}}= \frac{gR^{2}}{\left ( 2R \right )^{2}}= \frac{g}{4}}
The acceleration due to gravity at point P will be \mathrm{\left ( \frac{g}{4} \right )}

The correct answer is (2)

Posted by

Suraj Bhandari

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