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  • The initial speed of a projectile fired from ground is  At the highest point during its motion, t

The initial speed of a projectile fired from ground is \mathrm{u} At the highest point during its motion, the speed of projectile is\frac{\sqrt{3}}{2}\mathrm{u} . The time of flight of the projectile is :

Option: 1

\mathrm{\frac{2u}{g}}


Option: 2

\mathrm{\frac{u }{2g}}


Option: 3

\mathrm{\frac{\sqrt{3}u }{g}}


Option: 4

\mathrm{\frac{u }{g}}


Answers (1)

best_answer

At the highest point -

\mathrm{u\cos \theta =\frac{\sqrt{3}u}{2}}

\mathrm{\theta=30}

\mathrm{T=\frac{2u\sin \theta}{g}=\frac{u}{g}}

Posted by

Gaurav

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