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  • The minimum and maximum distances of a planet revolving around the Sun are . If the minimum speed of the planet on its trajectory is <img alt="\mathrm{v}_{0}" src="/latex

The minimum and maximum distances of a planet revolving around the Sun are x_{1}$ and $x_{2}. If the minimum speed of the planet on its trajectory is \mathrm{v}_{0} then its maximum speed will be :
 
Option: 1 \frac{\mathrm{v}_{0} \mathrm{x}_{1}^{2}}{\mathrm{x}_{2}^{2}}
Option: 2 \frac{\mathrm{v}_{0} \mathrm{x}_{2}^{2}}{\mathrm{x}_{1}^{2}}
Option: 3 \frac{v_{0} x_{1}}{x_{2}}
Option: 4 \frac{v_{0} x_{2}}{x_{1}}

Answers (1)

best_answer


In a given orbit , L = mvr = constant
\therefore mv_{1}x_{1}= mv_{2}x_{2}
v_{2}\rightarrow Minimum\, speed
(the speed at aphelion)
\therefore v_{2}= v_{0}
v_{1}= v_{maximum}= \frac{v_{2}x_{2}}{x_{1}}
v_{max}= \frac{v_{0}x_{2}}{x_{1}}
(at perihelion )
The correct option is (4)

Posted by

vishal kumar

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