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  • The mole fraction of glucose   in an aqueous binary solution is 0.1. The mass percentage of water in it to the nearest integer is-

The mole fraction of glucose (C_{6}H_{12}O_{6})  in an aqueous binary solution is 0.1. The mass percentage of water in it to the nearest integer is-
 

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Mole fraction of glucose, in C_{6}H_{12}O_{6}=0.1

Now, lets assume we have 10 moles of solution.

Thus, moles of C_{6}H_{12}O_{6}=1

Ans, moles of H_2O = 9

Now, the mass of water = number of moles x molar mass

Thus, the mass of water  \mathrm{= 9 \times 18 = 162 \ g}

Mass of C_{6}H_{12}O_{6}=180\: gm

Now, mass percent of water is given as:

\mathrm{Mass\: \%\: of\: water\: =\: \frac{Mass\: of\: water}{Mass\: of\: water\: +\: mass\: of\: glucose}\: x\: 100}

 \mathrm{Mass\: \%\: of\: water\: =\: \frac{162}{180 +\: 162}\: x\: 100}

\mathrm{Mass\: \%\: of\: water\: =\: 47.3\%}

Thus, the correct answer is 47.

Posted by

Kuldeep Maurya

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