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  • The nearer pointof hypermetropic eye is . The lens to be used for its correction sh

The nearer pointof hypermetropic eye is \mathrm{40\ cm}. The lens to be used for its correction should have the power:

Option: 1

\mathrm{+1.5\ D}


Option: 2

\mathrm{-1.5\ D}


Option: 3

\mathrm{+2.5\ D}


Option: 4

\mathrm{+0.5\ D}


Answers (1)

best_answer

Hypermetropia is correct by using convex lens. Focal length of lens used,\mathrm{f=+}(defected near point)
\mathrm{\begin{gathered} \mathrm{f}=+\mathrm{d}=+40 \mathrm{~cm} \\ \therefore \quad \text { Power of lens }=\frac{100}{\mathrm{f}(\mathrm{cm})}=\frac{100}{+40}=+2.5 \mathrm{D} \end{gathered}}

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Divya Prakash Singh

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