Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • The periodic time of rotation of a certain star is 22 days and its radius is <img alt="\mathrm{7 \times 10^8}" src="https://entrancecorner.oncodecogs.com/gif.latex?%5Cmathrm%7B7%20%5Ctimes%2010%5E8

The periodic time of rotation of a certain star is 22 days and its radius is \mathrm{7 \times 10^8} metres. If the wavelength of light emitted by its surface be \mathrm{4320 \AA}, the Doppler shift will be \mathrm{ ( 1 \, \, day = 86400\, \, \mathrm{sec})}

Option: 1

\mathrm{0.033 \AA}


Option: 2

\mathrm{0.33 \AA}


Option: 3

\mathrm{3.3 \AA}


Option: 4

\mathrm{33 \AA}


Answers (1)

best_answer

\mathrm{\begin{aligned} & \Delta \lambda=\lambda \cdot \frac{\mathrm{v}}{\mathrm{c}} \text { where } \mathrm{v}=\mathrm{r} \omega=\mathrm{r} \times\left(\frac{2 \pi}{\mathrm{T}}\right) \\ & \therefore \Delta \lambda=\frac{4320 \times 7 \times 10^8 \times 2 \times 3.14}{3 \times 10^8 \times 22 \times 86400}=0.033 \AA \end{aligned}}

Posted by

Anam Khan

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2026 final key soon; objection window closes today
anam-khan

100 marks in JEE Mains 2026 Percentile: Know rank trends, admission chances at NITs, IIITs
anam-khan

NIT vs GFTI: Which requires a lower JEE Main cutoff?

Latest Question