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  • The position of a particle related to time is given by  . n

The position of a particle related to time is given by x=(5t^{2}-4t+5)m .  The magnitude of velocity of the

particle at t = 2s will be :

Option: 1

10 ms^{-1}


Option: 2

6 ms^{-1}


Option: 3

16 ms^{-1}


Option: 4

14 ms^{-1}


Answers (1)

best_answer

Given, x=(5t^{2}-4t+5)m 

\begin{aligned} & \mathrm{V}=\frac{\mathrm{dx}}{\mathrm{dt}}=10 \mathrm{t}-4 \\ & \mathrm{t}=2, \mathrm{~V}=20-4 \\ & \mathrm{~V}=16 \mathrm{~m} / \mathrm{s} \end{aligned}


 

Posted by

seema garhwal

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