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  • The principal value of the given equation  <img alt="y=cot^{-1}\left ( \sqrt{3} \right )" src="https://entrancecorner.oncodecogs.com/gif.latex?y%3Dcot%5E%7B-1%7D%5Cleft%20%28%20%5Csq

The principal value of the given equation  y=cot^{-1}\left ( \sqrt{3} \right )   is

Option: 1

\frac{\pi}{6}


Option: 2

\frac{\pi}{3}


Option: 3

\frac{\pi}{2}


Option: 4

\frac{\pi}{4}


Answers (1)

best_answer

Given that,

y=cot^{-1}\left ( \sqrt{3} \right )

cot\ y=\left (\sqrt{3} \right)
We know that the range of the principal value branch of   cot^{-1}x  is  \left ( -\frac{\pi}{2},\frac{\pi}{2} \right ).

Thus,

cot\left ( \frac{\pi}{6} \right )=\sqrt{3}

Therefore, the principal value of   cot^{-1}\left ( \sqrt{3} \right )=\frac{\pi}{6}.


 

Posted by

Irshad Anwar

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