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The radii of two planets 'A' and 'B' are 'R' and '4R' and their densities are \mathrm{\rho \: \: and \: \: \rho /3 }respectively. The ratio of
acceleration due to gravity at their surfaces \mathrm{ (g_{A}: g_{B}) } will be :

Option: 1

1:16


Option: 2

3:16


Option: 3

3:4


Option: 4

4:3


Answers (1)

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\mathrm{g=\frac{4\pi }{3}GR\rho }

\mathrm{g \ \ \alpha \ \ \rho R }

\mathrm{\frac{g_{A}}{g_{B}}=\frac{\rho _{A}R_{A}}{\rho _{B}.R_{B}}=\frac{\rho .R}{\frac{\rho }{3}.4R}=\frac{3}{4} }

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Irshad Anwar

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