Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • The range of the projectile projected at an angle of   with horizontal is 50 m. If th

The range of the projectile projected at an angle of  15^{\circ} with horizontal is 50 m. If the projectile is projected with same velocity at an angle of  45^{\circ} with horizontal, then its range will be

Option: 1

100 \sqrt{2} \mathrm{~m}


Option: 2

50m


Option: 3

100m


Option: 4

50 \sqrt{2} \mathrm{~m}


Answers (1)

best_answer

\begin{aligned} & \text { So } R=\frac{\mathrm{u}^2 \sin (2 \times 15)}{\mathrm{g}}=\frac{\mathrm{u}^2}{2 \mathrm{~g}}=\text { So } \Rightarrow \frac{\mathrm{u}^2}{\mathrm{~g}}=100 \\ & R^{\prime}=\frac{\mathrm{u}^2 \sin (2 \times 45)}{\mathrm{g}}=\frac{\mathrm{u}^2}{\mathrm{~g}}=100 \mathrm{~m} \end{aligned}

Posted by

Irshad Anwar

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Latest Question