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  • The range of the projectile projected at an angle of   with horizontal is 50 m. If th

The range of the projectile projected at an angle of  15^{\circ} with horizontal is 50 m. If the projectile is projected with same velocity at an angle of  45^{\circ} with horizontal, then its range will be

Option: 1

100 \sqrt{2} \mathrm{~m}


Option: 2

50m


Option: 3

100m


Option: 4

50 \sqrt{2} \mathrm{~m}


Answers (1)

best_answer

\begin{aligned} & \text { So } R=\frac{\mathrm{u}^2 \sin (2 \times 15)}{\mathrm{g}}=\frac{\mathrm{u}^2}{2 \mathrm{~g}}=\text { So } \Rightarrow \frac{\mathrm{u}^2}{\mathrm{~g}}=100 \\ & R^{\prime}=\frac{\mathrm{u}^2 \sin (2 \times 45)}{\mathrm{g}}=\frac{\mathrm{u}^2}{\mathrm{~g}}=100 \mathrm{~m} \end{aligned}

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Irshad Anwar

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