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The speed of a swimmer is \mathrm{4 km h^{-1}} in still water. If the swimmer makes his strokes normal to the flow of river of width \mathrm{1 km }, he reaches a point \mathrm{750m } down the stream on the opposite bank. The speed of the river water is _______\mathrm{ kmh^{-1} }

Option: 1

3


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

\mathrm{T=\frac{D}{V}=\frac{1}{4}hr}

\mathrm{Drift=uT}

\mathrm{\frac{750}{1000}kM=u\times \frac{1}{4}hr}

\mathrm{u=3km/hr}

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mansi

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