Get Answers to all your Questions

header-bg qa

The time period of a satellite revolving around earth in a given orbit is 7 hours. If the radius of orbit is increased to three times its previous value, then approximate new time period of the satellite will be

Option: 1

\mathrm{40 \text { hours }}


Option: 2

\mathrm{36 \text { hours }}


Option: 3

\mathrm{30 \text { hours }}


Option: 4

\mathrm{25 \text { hours }}


Answers (1)

best_answer

\mathrm{T^{2} \alpha R^{3}} \\

\mathrm{\frac{T_{1}{ }^{2}}{T_{2}{ }^{2}}=\left(\frac{R_{1}}{R_{2}}\right)^{3}}

\mathrm{\left(\frac{7}{T_{2}}\right)^{2} =\left(\frac{R}{3 R}\right)^{3}} \\

\mathrm{\frac{49}{T_{2}{ }^{2}} =\frac{1}{27}} \\

\mathrm{T_{2}^{2} =49 \times 27} \\

\mathrm{T_{2} =\sqrt{49 \times 27}=7 \times 3 \sqrt{3}} \\

\mathrm{=36 \text { hrs }}

Hence correct answer is option 2

Posted by

rishi.raj

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE