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  • The train runs in a straight line with a constant acceleration "a". A girl standing in a tra

The train runs in a straight line with a constant acceleration "a". A girl standing in a train throws a ball forward at a speed of  10\ \frac{m}{s} at an angle of  600 degrees from the horizontal. The girl must advance 1.15\ meters inside the train to catch the ball at the initial height. The acceleration of the train, in  
\frac{m}{s^2}, is:

Option: 1

5\ \frac{m}{s^2}


Option: 2

10\ \frac{m}{s^2}


Option: 3

20\ \frac{m}{s^2}


Option: 4

25\ \frac{m}{s^2}


Answers (1)

best_answer

R=\frac{1}{2}at^2+1.15

u^2\frac{sin2\theta}{g}=\frac{1}{2}a\left(2sin\frac{\theta}{g}\right)^2+\ 1.15

Or, \frac{100\times\frac{\sqrt3}{2}}{10}=\frac{1}{2}a\left(\frac{4\times100\times\frac{3}{4}}{100}\right)+1.15

Or, 2\times5\sqrt3=3a+2.30

Or, 10\sqrt3=3a+2.30

Or, 10\times1.73-2.3\ =3a

Or, 17.3\ -2.3\ =3a

Or, a= 5\ \frac{m}{s^2}

 

 

Posted by

chirag

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