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  • The width of fringe is on the screen in a double slits experiment for the light of wavele

The width of fringe is 2 \mathrm{~mm} on the screen in a double slits experiment for the light of wavelength of 400 \mathrm{~nm}.The width of the fringe for the light of wavelength 600 \mathrm{~nm} will be:

Option: 1

1.33 \mathrm{~mm}


Option: 2

3 \mathrm{~mm}


Option: 3

2 \mathrm{~mm}


Option: 4

4 \mathrm{~mm}


Answers (1)

best_answer

\beta=\frac{D \lambda}{d}

\Rightarrow \beta \propto \lambda

\frac{\beta_{1}}{\beta_{2}}=\frac{\lambda_{1}}{\lambda_{2}} \Rightarrow \frac{2}{\beta}=\frac{400}{600}

\beta=3 \mathrm{~mm}

Posted by

Ajit Kumar Dubey

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