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Two angles of a triangle are 45^{\circ}  and  90^{\circ} and the side opposite the first angle is 35; find the side opposite the latter angle.

Option: 1

36\sqrt{2}


Option: 2

37\sqrt{2}


Option: 3

35\sqrt{2}


Option: 4

38\sqrt{2}


Answers (1)

best_answer

Given that,

Two angles of a triangle are 45^{\circ}  and 90^{\circ}.

The side opposite the first angle is 35.

Using the sine formula,

 \frac{a}{sin\ A}=\frac{b}{sin\ B}

\frac{35}{sin\ 45^{\circ}}=\frac{b}{sin\ 90^{\circ}}

 b=\frac{35}{\left ( \frac{1}{\sqrt{2}} \right )}

b=35\sqrt{2}

 

Posted by

Pankaj

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