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  • Two beams of light having intensities I and interferes. The phase difference between the beams

Two beams of light having intensities I and 4 \mathrm{I} interferes. The phase difference between the beams is \pi / 2 at point \mathrm{A} and \mathrm{\pi} at point \mathrm{\mathrm{B}}. Then, the difference between the resultant intensities at \mathrm{A} and \mathrm{B} is:

Option: 1

2I


Option: 2

4I


Option: 3

5I


Option: 4

9I


Answers (1)

best_answer

\mathrm{\begin{aligned} & \Delta I=\left(I_1+I_2+2 \sqrt{I_1 I_2} \cos \phi_1\right)-\left(I_1+I_2+2 \sqrt{I_1 I_2} \cos \phi_2\right) \\\\ & =2 \sqrt{I_1 I_2}\left(\cos \phi_1-\cos \phi_2\right)=2 \times 2 I\left(\cos \frac{\pi}{2}-\cos \pi\right)=4 I \end{aligned}}

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Rakesh

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