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  • Two light beams of intensities in the ratio of 9 : 4 are allowed to interfere. The ratio of the intensity of maxima and minima will be:Option: 1 2:3<

Two light beams of intensities in the ratio of 9 : 4 are allowed to interfere. The ratio of the intensity of maxima and minima will be:

Option: 1

2:3


Option: 2

16:81


Option: 3

25:169


Option: 4

25:1


Answers (1)

best_answer

\mathrm{\begin{aligned} &\frac{I_{1}}{I_{2}}=\frac{9}{4}\\ &\frac{I_{\text {max }}}{I_{\text {min }}}=\frac{\left(\sqrt{I_{1}}+\sqrt{I_{2}}\right)^{2}}{\left(\sqrt{I_{1}}-\sqrt{I_{2}}\right)^{2}}=\frac{25}{1} \end{aligned} }
The correct option is (4)

Posted by

Sanket Gandhi

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