Get Answers to all your Questions

header-bg qa

Two objects of equal masses placed at certain distance from each other attracts each other with a force of F. If one-third mass of one object is transferred to the other object, then the new force will be :

Option: 1

\mathrm{\frac{2}{9} \mathrm{~F}}


Option: 2

\mathrm{\frac{16}{9} \mathrm{~F}}


Option: 3

\mathrm{\frac{8}{9} \mathrm{~F}}


Option: 4

\mathrm{\mathrm{F}}


Answers (1)

Case-1

\mathrm{F=\frac{Gm^{2}}{d^{2}}}

Case-2

\mathrm{m+m/3=\frac{4m}{3}}                 \mathrm{m-m/3=2m/3}

\mathrm{F^{\prime}=\frac{G \times \frac{4m}{3} \times \frac{2 m}{3}}{d^{2}}=\frac{8}{9} \frac{\operatorname{Gm}^{2}}{d^{2}}=\frac{8}{9} F}

Hence the correct option is 3

Posted by

Kshitij

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE