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  • Two projectiles are projected at and <img alt="60^{\circ}" src="https://entrancecorner.oncodec

Two projectiles are projected at 30^{\circ} and 60^{\circ} with the horizontal the same speed. The ratio of the maximum height attained by the two projectiles respectively is:

Option: 1

2: \sqrt{3}


Option: 2

1: \sqrt{3}


Option: 3

\sqrt{3}: 1


Option: 4

1: 3


Answers (1)

best_answer

In projectile motion, \mathrm{H}_{\text {many }}=\frac{\mathrm{u}^2 \sin ^2 \theta}{2 \mathrm{~g}}

at

 \begin{array}{ll} \theta=30^{\circ}, & \mathrm{H}_1=\frac{\mathrm{u}^2 \sin ^2 30^{\circ}}{2 \mathrm{~g}} \\ \theta=60^{\circ}, & \mathrm{H}_2=\frac{\mathrm{u}^2 \sin ^2 60^{\circ}}{2 \mathrm{~g}} \end{array}

\frac{\mathrm{H}_1}{\mathrm{H}_2}=\frac{\sin ^2 30^{\circ}}{\sin ^2 60^{\circ}}=\frac{\left(\frac{1}{2}\right)}{\left(\frac{\sqrt{3}}{2}\right)^2}=\frac{1}{3}

 

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Gunjita

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