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  • Two satellites  having masses in the ratio <img alt="\mathrm

Two satellites \mathrm{A\: and\: B} having masses in the ratio \mathrm{ 4: 3, } are revolving in circular orbits of radii \mathrm{ 3 \mathrm{r}} and \mathrm{ 4 \mathrm{r}} respectively around the earth. The ratio of total mechanical energy of \mathrm{ A} to \mathrm{ B} is:

Option: 1

9: 16


Option: 2

16: 9


Option: 3

1: 1


Option: 4

4: 3


Answers (1)

best_answer

Total mechanical energy is \mathrm{T E=-\frac{P E}{2}}
for satellite 1 ,

\mathrm{ T E_1=\frac{-G M m_1}{2(3 r)} }

For satellite 2,

\mathrm{T E_2=\frac{-G M m_2}{2(4r)} }

\mathrm{\frac{T E_1}{T E_2}=\frac{8 m_1}{6 m_2}=\frac{4}{3} \times \frac{4}{3}=\frac{16}{9}}

Hence 2 is correct option.

Posted by

himanshu.meshram

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