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Two slits separated by a distance of 1 \mathrm{~mm}, are illuminated with red light of wavelength \mathrm{6.5 \times 10^{-7} \mathrm{~m}}. The interference fringes are observed on a screen placed \mathrm{1 \mathrm{~m}} from the slits. The distance between the third dark fringe and the fifth bright fringe is equal to:

Option: 1

0.65 mm


Option: 2

1.63 mm


Option: 3

3.25 mm


Option: 4

4.88 mm


Answers (1)

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\mathrm{\begin{aligned} & \Delta \mathrm{Y}=\frac{5 \lambda \mathrm{D}}{\mathrm{d}}-\frac{5 \lambda \mathrm{D}}{2 \mathrm{~d}}=\frac{5 \lambda \mathrm{D}}{2 \mathrm{~d}} \\\\ & =\frac{5 \times 6.5 \times 10^{-7} \times 1}{2 \times 10^{-3}} \mathrm{~m}=1.63 \mathrm{~mm} \end{aligned}}

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HARSH KANKARIA

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