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What amount of Acetic Acid \mathrm{(CH_3COOH)} should be added to sufficient water to obtain a 1 litre solution having pH = 3?

\mathrm{(Given, \ Ka\ of\ CH_3COOH = 10^{-5})}

Option: 1

6 g


Option: 2

30 g


Option: 3

60 g


Option: 4

120g


Answers (1)

best_answer

\mathrm{CH_3COOH \rightleftharpoons CH_3COO^- + H^+, Ka =10^{-5}}

        c                                0                    0

        (c-x)                          x                    x

        ~ (c)

Given, pH = 3,

Thus \mathrm{[H]^+ =10^{-3} = x}

Now, from the expression of the equilibrium constant,

        \mathrm{\frac{x^2}{c}= 10^{-5}}

\Rightarrow\mathrm{\frac{10^{-6}}{c}= 10^{-5}}

\Rightarrow\mathrm{{c}= 10^{-1}}

Thus, the given solution is 0.1 M in Acetic acid.

Hence, moles of Acetic acid in 1 litre solution = 0.1

Thus, the mass of Acetic Acid = 6 g

Hence, the correct answer is Option (1)

Posted by

Irshad Anwar

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