What is Gravitational potential due to uniform circular disc at a point on its Axis ??

Answers (1)

As shown in the below figure

Gravitational potential due to uniform circular disc at a point on its axis is given by

        V=-\frac{2GM}{a^2}(\sqrt{a^2+x^2}-x)

Where

a \rightarrow Radius of disc

x- position of point on the axis of the disc

M-mass of disc

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