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  • Find the HCF of $\frac{36}{51}$ and $3 \frac{9}{17}$.Option: 1 12/17Option: 2 19/13</di

Find the HCF of $\frac{36}{51}$ and $3 \frac{9}{17}$.

Option: 1

12/17


Option: 2

19/13


Option: 3

12/13


Option: 4

11/17


Answers (1)

best_answer

Here, $\frac{36}{51}=\frac{12}{17}$ and $3 \frac{9}{17}=\frac{60}{17}$

Now, we have to find the HCF of $\frac{12}{17}$ and $\frac{60}{17}$

According to the formula, 

HCF of fractions = $\frac{H C F \text { of Numerators }}{L C M \text { of Denominators }}=\frac{H C F \text { of } 12 \text { and } 60}{L C M \text { of } 17 \text { and } 17}=\frac{12}{17}$

Posted by

Rakesh

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