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HCF of $\left(\frac{9}{25}, \frac{12}{35}, \frac{18}{10}, \frac{21}{40}\right)$ is:
Option: 1
$\frac{3}{5}$

Option: 2
$\frac{252}{5}$

Option: 3
$\frac{3}{1400}$

Option: 4
$\frac{63}{700}$

Answers (1)

best_answer

HCF of $(9 / 25,12 / 35,18 / 10,21 / 40)=$ HCF of numerator/ LCM of denominator

$=3 / 1400$

Posted by

Gunjita

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