The HCF of $\left(\frac{3}{4}, \frac{5}{6}, \frac{6}{7}\right)$ is
$\frac{2}{93}$
$\frac{1}{84}$
$\frac{1}{83}$
$\frac{3}{91}$
HCF of $(3 / 5,5 / 6,6 / 7)=$ HCF of numerator/ LCM of denominator
$=1 / 84$
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