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The HCF of $\left(\frac{3}{4}, \frac{5}{6}, \frac{6}{7}\right)$ is
Option: 1
$\frac{2}{93}$

Option: 2
$\frac{1}{84}$

Option: 3
$\frac{1}{83}$

Option: 4
$\frac{3}{91}$

Answers (1)

best_answer

HCF of $(3 / 5,5 / 6,6 / 7)=$ HCF of numerator/ LCM of denominator

$=1 / 84$

Posted by

manish painkra

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