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The HCF of $\left(\frac{3}{4}, \frac{5}{6}, \frac{6}{7}\right)$ is

Option: 1

$\frac{2}{93}$


Option: 2

$\frac{1}{84}$


Option: 3

$\frac{1}{83}$


Option: 4

$\frac{3}{91}$


Answers (1)

best_answer

HCF of $(3 / 5,5 / 6,6 / 7)=$ HCF of numerator/ LCM of denominator

$=1 / 84$

Posted by

manish painkra

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