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  • 0.16 g of dibasic acid required 25 ml of decinormal solution for complete neutralisation. The modecular weight of the acid will be<div class='qna-opt

0.16 g of dibasic acid required 25 ml of decinormal NaOH solution for complete neutralisation. The modecular weight of the acid will be

Option: 1

32


Option: 2

64


Option: 3

128


Option: 4

256


Answers (1)

best_answer

According to law of equivalence,

milli equivalents of Acid = milli equivalents of Base

\Rightarrow \frac{0.16}{M} \times 2 \times 1000 = 25 \times 0.1

\Rightarrow M= 128 \ g\ mol^{-1}

 

Posted by

Ajit Kumar Dubey

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