Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Medical
  • 0.16 g of dibasic acid required 25 ml of decinormal solution for complete neutralisation. The modecular weight of the acid will be<div class='qna-opt

0.16 g of dibasic acid required 25 ml of decinormal NaOH solution for complete neutralisation. The modecular weight of the acid will be

Option: 1

32


Option: 2

64


Option: 3

128


Option: 4

256


Answers (1)

best_answer

According to law of equivalence,

milli equivalents of Acid = milli equivalents of Base

\Rightarrow \frac{0.16}{M} \times 2 \times 1000 = 25 \times 0.1

\Rightarrow M= 128 \ g\ mol^{-1}

 

Posted by

Ajit Kumar Dubey

View full answer

NEET 2024 Most scoring concepts

    Just Study 32% of the NEET syllabus and Score up to 100% marks

Similar Questions

Trending Articles/News

anam-khan

Aiming for 650+ in NEET 2025? Focus on these high-weightage chapters
anam-khan

Sri Chaitanya Academy, Infinity Learn launch NEET preparation course, 'ATREYA'
anam-khan

Lowest NEET cut-off for MBBS in Maharashtra government medical colleges; passing mark out of 720

Latest Question