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  • 1 mde of a monoatomic gas is mixed with 2 mole of a diatomiz gas <img

1 mde of a monoatomic gas \left ( x= \frac{5}{3} \right ) is mixed with 2 mole of a diatomiz gas \left ( x= \frac{7}{5} \right ), the value of x for the mixture is
 

 

 

Option: 1

1.40


Option: 2

1.50


Option: 3

1.53

 


Option: 4

1.46


Answers (1)

best_answer

The correct option is (4)

\frac{\left(n_{1}+n_{2}\right)}{k_{\text {mix }-1}}=\frac{n_{1}}{x_{1-1}}+\frac{n_{2}}{x_{2}-1}

\frac{3}{x_{\text {mix-1 }}^{2}}=\frac{1}{\frac{5}{3}-1}+\frac{2}{\frac{7}{5}-1}=\frac{3}{2}+\frac{10}{2}=\frac{13}{2}

\begin{aligned} &\frac{6}{13}=x_{\operatorname{mix}}^{2}-1 \\ &x_{\operatorname{mix}}=\frac{6}{13}+1=\frac{19}{13}=1.46 \end{aligned}

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avinash.dongre

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