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  • 22g of CO2 gas at 27 oC is mixed with 16g of O2 gas at 37 oC. What will be the temperature of

22g of CO2 gas at 27 oC is mixed with 16g of O2 gas at 37 oC. What will be the temperature of the mixture?

Option: 1

36 oC


Option: 2

32oC


Option: 3

273K


Option: 4

274K


Answers (1)

best_answer

22 \mathrm{~g} \mathrm{Of} \mathrm{CO}_2=\frac{22}{44}=\frac{1}{2} \mathrm{~mol} \mathrm{of} \mathrm{CO}_2

16 \mathrm{~g} \text { of } \mathrm{O}_2=\frac{16}{32}=\frac{1}{2} \text { mol of } \mathrm{O}_2

Temperature \begin{aligned} & \text { Of the mixture, } \\ & T=\frac{n_1 T_1+n_2 T_2}{n_1+n_2}=\frac{\frac{1}{2}(27+273)+\frac{1}{2}(37+273)}{\frac{1}{2}+\frac{1}{2}} \end{aligned}

  =305 K

  = 32 oC

Posted by

chirag

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