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  • 39. An ideal gas is initially at temperature T and volume V. Its volume is increased by V due to an increase in temperature T, pressure remaining constant. The quantity <img alt="\mathrm{\delta=\De

39. An ideal gas is initially at temperature T and volume V. Its volume is increased by V due to an increase in temperature T, pressure remaining constant. The quantity \mathrm{\delta=\Delta V /(V \Delta T)} varies with temperature as (see Figs.)

Option: 1


Option: 2


Option: 3


Option: 4


Answers (1)

best_answer

For an ideal gas, PV = nRT. Since pressure P is kept constant,
PΔV = n RΔT

\mathrm{\begin{aligned} & \text { Or } \frac{\Delta V}{\Delta T}=\frac{n R}{P}=\frac{n R V}{n R T}=\frac{V}{T}\left(\because P=\frac{n R T}{V}\right) \\ & \text { Or } \frac{1}{V} \frac{\Delta V}{\Delta T}=\frac{1}{T} \text { or } \delta=\frac{1}{T} \end{aligned}}

Thus, the value of δ decreases as T is increased
Hence the correct choice is (c)

Posted by

Kuldeep Maurya

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