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  • 4 m solution of the aqueous solution is cooled to . Calculate

4 m solution of the aqueous solution is cooled to 8.45^{\circ} \mathrm{C}. Calculate the mass per cent of water present in the solution, which will as ice ( \mathrm{k_f} \; \text{of water} =1.86 \mathrm{k}-\mathrm{kg} / \mathrm{mol} )

Option: 1

22.4 %


Option: 2

50 %


Option: 3

92 %


Option: 4

80 %


Answers (1)

best_answer

\begin{aligned} & \mathrm{\Delta T_f=k_f m=k_f \cdot \frac{n _\text {solute }}{kg_ \text { solvent }}} \\ \\& 8.45=1.86 \times \frac{4}{\text{kg} _\text { solvent }} \\ \\& \frac{8.45}{1.86}=\frac{4}{\text{kg} _\text { solvent }} \\ \\& 4.54=\frac{4}{\text{kg}_ \text { solvent }} \end{aligned}

\begin{aligned} & \text { kg} _\text{solvent }=\frac{4}{4.54} \\ \\& \text { kg} _\text{solvent }=0.8 \end{aligned}

The mass per cent of water separated as 

   0.8 \times 100

  =80%

Posted by

HARSH KANKARIA

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