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  • A  0.0050 m aqueous solution of an ionic compound <img alt="\mathrm{CO}\left(\mathrm{NH}_3\right)_5\mathrm{NO}_2" src="/latex-image/?%5Cmathrm%7BCO%7D%5Cleft%28%5Cmathrm%7BNH%7D_3%5Cright

A  0.0050 m aqueous solution of an ionic compound \mathrm{CO}\left(\mathrm{NH}_3\right)_5\mathrm{NO}_2 freezes at 0.00862^{\circ} \mathrm{C} What will be the number of moles of ions which 1 mole of ionic compound produces \mathrm{\left(k_f=1.86^{\circ} \mathrm{c} / \mathrm{m}\right)}

Option: 1

i = 0.341


Option: 2

i = 0.528


Option: 3

i = 0.64


Option: 4

i = 0.92


Answers (1)

best_answer

\\ \mathrm{\Delta T_f =i K_f m} \\ \\\mathrm{i =\frac{\Delta T_f}{K_f \times m}} \\\\ \\\text{i} =\frac{0.00862}{1.86 \times 0.005} \\ \\\text{i} =0.9

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SANGALDEEP SINGH

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