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A 1 Kg ball moving with 12 m/s . collides head on with 2 Kg ball moving in opposite direction at 24 m/s if the coefficient of restitution is 2/3 the how much energy (Joule) is lost in collision 

Option: 1

240


Option: 2

120


Option: 3

360


Option: 4

400


Answers (1)

best_answer

As we have learned

Inelastic Collision -

e< 1

- wherein

\! e\: :\: coeffecient\: of \: restitution

 

 \Delta E = \frac{1}{2} \frac{m_1m_2}{m_1+m_2} (1-e^2) (u_1-u_2 )^2

\Delta E = \frac{1}{2}\times \frac{2}{3} (1-\frac{4}{9}) (12+24)^2= 240 J

Posted by

shivangi.bhatnagar

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