Get Answers to all your Questions

header-bg qa

A 10 lithe contruncr at 500 \times contains \left(\mathrm{O}_{2}[9]\right.  at beosowo.4 \mathrm{~atm} and an excess sro E Neglect the volume at solid san?.
The volume of the contend io Now decreased by Mewing the marble Piston filled in the container. The Maxim, volume as the container, ween the bessie of in allows it a Maximum value?

 

Option: 1

5 L


Option: 2

2.3 L


Option: 3

4 L


Option: 4

3.5 L


Answers (1)

best_answer

Max. Pressure of \mathrm{C}_{2}=\mathrm{Pressure \: of \: \mathrm{CO}_{2}} equilibrium for reaction
\begin{aligned} & \mathrm{SrCO}_{3}(\mathrm{~s})=\mathrm{srO}(\mathrm{S})+\mathrm{CO} 2 \\ & V=\frac{n R T}{P}-(i) \\ & k_{p}=P\left(O_{2}=1.6 \text { atm }=\text { Max. Pressure ot } \mathrm{Co}_{2}\right. \end{aligned}

The volume at container is sealed and the Reaction was not earlier at equilibrium
\begin{aligned} & n=\text { constant } \\ & n=\frac{P_{V}}{\beta_{T}}=\frac{.4 \times 10}{\beta_{T}}-(\text { ii) } \end{aligned}
 \text{Put equation }(i) \rightarrow (ii)
\mathrm{V=\frac{4 \times 10}{R T} \times \frac{R T}{1-6}=2.5 \mathrm{~L}}

Posted by

admin

View full answer

NEET 2024 Most scoring concepts

    Just Study 32% of the NEET syllabus and Score up to 100% marks