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  • A ball of mass m and radius r is gently released in a viscous liquid. The mass of the liquid displaced by it is <img alt="\mathrm{m^{\prime} }" src="https://entrancecorner.oncodecogs.com/

A ball of mass m and radius r is gently released in a viscous liquid. The mass of the liquid displaced by it is \mathrm{m^{\prime} }such that \mathrm{m>m^{\prime}.} The terminal velocity is proportional to

Option: 1

\mathrm{\frac{m-m^{\prime}}{r}}


Option: 2

\mathrm{\frac{m+m^{\prime}}{r}}


Option: 3

\mathrm{\frac{\left(m+m^{\prime}\right)}{r^2}}


Option: 4

\mathrm{\left(m-m^{\prime}\right) r^2}


Answers (1)

best_answer

\mathrm{\begin{aligned} & m g=m^{\prime} g+6 \pi \eta r v \\ & \frac{m-m^{\prime}}{r} \times v \end{aligned}}

Posted by

avinash.dongre

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