Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Medical
  • A beam of uniform density of length ' L '  is  hanging vertically with the help of the pivot as shown in the figure. At what length below the pivot an impulse should be

A beam of uniform density of length ' L '  is  hanging vertically with the help of the pivot as shown in the figure. At what length below the pivot an impulse should be applied such that it does not experiences shock at the hinge.

Option: 1

\frac{L}{3}


Option: 2

\frac{2 L}{3}


Option: 3

\frac{L}{6}


Option: 4

\frac{5L}{6}


Answers (1)

best_answer

y=\frac{I_{C M}}{M(L / 2)}=\frac{\frac{1}{1 2} M L^2}{\frac{M L}{2}}

y=\frac{L}{6}

height of the point below the pivot  =\frac{L}{6}+\frac{L}{2}=\frac{2 L}{3}

Posted by

Deependra Verma

View full answer

NEET 2024 Most scoring concepts

    Just Study 32% of the NEET syllabus and Score up to 100% marks

Similar Questions

Trending Articles/News

anam-khan

NEET UG 2026 Tie-Breaking Rule Explained: Here’s how ranks are decided
anam-khan

NEET 2026: Odisha aspirant dies by suicide fearing failure
anam-khan

NEET 2026 Answer Key (Out) LIVE: NTA to open challenge window shortly; direct link, result date, counselling

Latest Question