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  • A body is executing simple harmonic motion with frequency 'n' the frequency of its potential energy is:Option: 1 <img alt="n" src="/latex-ima

A body is executing simple harmonic motion with frequency 'n' the frequency of its potential energy is:

Option: 1

n


Option: 2

2n


Option: 3

3n


Option: 4

4n


Answers (1)

best_answer

x=A \sin \omega t

P E=\frac{1}{2} m \omega^{2} x^{2}=\frac{1}{2} m \omega^{2} A^{2}\left [ \frac{1-\cos 2\omega t}{2} \right ]

p E=\frac{1}{4} m\omega ^{2} A^{2}[1-\cos (20\omega t)]

            \omega=2 \pi n

P E=\frac{1}{4} m \omega^{2} A^{2}[1-\cos (4\pi n t)]

Angular frequency of PE is 2\omega

\therefore Frequency=2n

Posted by

Riya

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