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  • A body of mass 5kg hangs from a spring and oscillate with a time peiod of  seconds. If the body is removed, the length of the spring will

A body of mass 5kg hangs from a spring and oscillate with a time peiod of 2\pi seconds. If the body is removed, the length of the spring will decrease by -

Option: 1

\frac{g}{k}m


Option: 2

\frac{k}{g}m


Option: 3

2\pi m


Option: 4

g \;m


Answers (1)

best_answer

T = 2\pi \sqrt{\frac{m}{K}} = 2\pi     or       \frac{m}{z} = 1

In equilibrium, 

mg = kd

d= \frac{mg}{K} = 1\times g = g \;metres

Posted by

Irshad Anwar

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