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  • A Carnot engine, having an efficiency of as heat engine is used as a refrigerator. If the work do

A Carnot engine, having an efficiency of \eta=1 / 10 as heat engine is used as a refrigerator. If the work done on the system is 10 \mathrm{~J}, the amount of energy absorbed from the reservoir at lower temperature is

Option: 1

100 \mathrm{~J}


Option: 2

99 \mathrm{~J}


Option: 3

90 \mathrm{~J}


Option: 4

1 \mathrm{~J}


Answers (1)

best_answer

\mathrm{\frac{Q_{2}}{Q_{1}}=\frac{T_{2}}{T_{1}}}

\mathrm{\Rightarrow \frac{Q_{1}+W}{Q_{1}} =\frac{T_{2}}{T_{1}}}

\mathrm{\Rightarrow \frac{Q_{1}+10}{Q_{1}} =\frac{10}{9} }

\mathrm{\Rightarrow 9 Q_{1}+90 =10 Q_{1} }

\mathrm{\Rightarrow 90 =Q_{1} }

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