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  • A circular loop of mass '1kg' and radius '1m' rests on a horizontal smooth surface. A particle of mass '1kg' is moving with velocity '30m/s', strikes the loop and ge

A circular loop of mass '1kg' and radius '1m' rests on a horizontal smooth surface. A particle of mass '1kg' is moving with velocity '30m/s', strikes the loop and gets embedded in it. Find the angular velocity of the loop just after the particle hits it.

Option: 1

10rad/s


Option: 2

20rad/s


Option: 3

30rad/s


Option: 4

40rad/s


Answers (1)

best_answer

Conserving angular momentum about the combined centre of mass.

m v\left(\frac{R}{2}\right)=\left[m\left(\frac{R}{2}\right)^2+m R^2+m\left(\frac{R}{2}\right)^2\right] \omega

\omega = \frac{v}{r} = 10rad/s

Posted by

vishal kumar

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