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A closed hollow insulated cylinder is filled with gas at 0^{\circ} \mathrm{C} and also contains an insulated piston of negligible weight and negligible thickness at the middle point. The gas on one side is heated to 100^{\circ} \mathrm{C}. If the piston moves through 5 c m, the length of the follow cylinder is

Option: 1

13.65 cm


Option: 2

27.3 cm


Option: 3

38.6 cm


Option: 4

64.6 cm


Answers (1)

best_answer

Let L be the length (in cm) of the hollow cylinder and r its radius. Since the mass of the
gas remains unchanged and the pressures of the gas in both sides are equal, we have,
from Charle’s law,

\mathrm{\frac{V_1}{T_1}=\frac{V_2}{T_2}}                ...[1]

\mathrm{\text { Given } V_1=\left(\frac{L}{2}-5\right) \pi r^2, V_2=\left(\frac{L}{2}+5\right) \pi r^2 \text {, }}

\mathrm{T_1=0^{\circ} \mathrm{C}=273 \mathrm{Kand} T_2=100^{\circ} \mathrm{C}=373 \mathrm{~K} \text {. Using these values in (1), we get }}

\mathrm{\frac{\frac{L}{2}-5}{273}=\frac{\frac{L}{2}+5}{373}}

Which gives L = 64.6 cm

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manish

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