Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Medical
  • A constant pressure P is applied on all sides of a sphere at a certain temperature. By what amount should the temperature of the sphere by raised in order to bring its volume to the value it h

A constant pressure P is applied on all sides of a sphere at a certain temperature. By what amount should the temperature of the sphere by raised in order to bring its volume to the value it had before the pressure was applied? The coefficient of volume expansion of the material of the sphere is \mathrm{\alpha} and its compressibility is \mathrm{\sigma.}

Option: 1

\mathrm{\frac{\sigma P}{\alpha}}


Option: 2

\mathrm{\frac{\alpha P}{\sigma}}


Option: 3

\mathrm{\alpha \sigma P}


Option: 4

\mathrm{\frac{P}{\alpha \sigma}}


Answers (1)

best_answer

Let V be the original volume of the sphere. The decrease in volume under excess pressure P is

                      \mathrm{ \Delta V=\frac{V P}{B}=\sigma V P \quad\left(\because \sigma=\frac{1}{B}\right) }
where B is the bulk modulus. Let \Delta T be the increase in temperature to compensate for this increase in volume.
Then

                                     \mathrm{ \Delta V=\alpha V \Delta T }

Equating the two expression of \mathrm{\Delta V}, we get \mathrm{\Delta T=\frac{\sigma P}{\alpha}}

So the correct choice is (a).

Posted by

Rishabh

View full answer

NEET 2024 Most scoring concepts

    Just Study 32% of the NEET syllabus and Score up to 100% marks

Similar Questions

Trending Articles/News

anam-khan

'Years of hard work wasted': NEET aspirants, parents and teacher react to exam cancellation
anam-khan

CBI registers FIR in alleged NEET UG 2026 paper leak case after NTA cancels examination
anam-khan

Telangana doctors’ group, FAIMA condemn NEET UG 2026 paper leak, call it ‘complete systemic failure’

Latest Question