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  • A container of volume 2.24 L can with stand a Maximum Pressure of atm at before explodi

A container of volume 2.24 L can with stand a Maximum Pressure of atm at 298 \mathrm{~K} before exploding The Maximum Amount of oxygen sing) that can be safety put in this container at this temperature is closet to?

Option: 1

2.88


Option: 2

4.2


Option: 3

2.66


Option: 4

1.4


Answers (1)

best_answer

From an ideal gas \mathrm{P_{V}=n R T}
Maximum Number of Moles in container, \mathrm{n=\frac{P_{v}}{R_{T}}}
\mathrm{n=\frac{1 \times 2.24}{082 \times 298}=\frac{2.24}{24.4}=.091 \text { } }

\mathrm{=\text { Max weight of oxygen in container} =09 \times 32 }
                                                                                    \mathrm{=2.88 \mathrm{~g} }

At \mathrm{=2.88 \mathrm{~g} }     exploding can accur.
Thus, It must be less than \mathrm{=2.88 \mathrm{~g} }. Thus,  the Maximum Amount of oxygen that can be safety Put in this contemns at 298 Temperature and exert Presume less than 1 atm will be closed to undefined.

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vinayak

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