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A cylinder contains hydrigen gas at pressure of 249 kPa and temperature 27^oC.

Its density is: $\left(\mathrm{R = 8.3 Jmol^{-1}K^{-1}} \right )$

Option: 1
0.5 kg/m³

Option: 2
0.2 kg/m³

Option: 3
0.1 kg/m³

Option: 4
0.02 kg/m³

Answers (1)

best_answer

$\begin{aligned} & P v=n R T \\ \Rightarrow P V &=\frac{w}{M} R T \\ \Rightarrow P &=\frac{w}{M} \times \frac{R T}{V}=\frac{d R T}{M} \ \ \ [\because M=2 g/mol\ and T=273+27=300K]\\ \Rightarrow d=\frac{P M}{R T} &=\frac{249 \times 10^{3} \times 2 \times 10^{-3}}{8.3 \times 300} \\ &=0.2 \mathrm{Kg} / \mathrm{m}^{3} \end{aligned}$

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