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A cylindrical tank is filled with water to a level of 3 \mathrm{~m}. A hole is opened at a height of 52.5 \mathrm{~cm} from bottom. The ratio of the hole to that of gross sectional area of cylinder is 0.1 . Find the square of velocity with which water is coming out: \left(g=10 \mathrm{~m} / \mathrm{s}^{\wedge} 2\right. )

Option: 1

\mathrm{50 \mathrm{~m}^2 / \mathrm{s}^2}


Option: 2

\mathrm{40 \mathrm{~m}^2 / \mathrm{s}^2}


Option: 3

\mathrm{51.5 \mathrm{~m}^2 / \mathrm{s}^2}


Option: 4

\mathrm{50.5 \mathrm{~m}^2 / \mathrm{s}^2}


Answers (1)

best_answer

\mathrm{\frac{2 \mathrm{gh}}{1-\frac{\mathrm{a}^2}{\mathrm{~A}^2}}=\frac{2 \times 10 \times 2.475}{.99}}

Posted by

vinayak

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