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A disc of mass ' 1 Kg ' and radius ' 1 m ' is placed over the plank of mass '1 Kg '. A force of constant magnitude of  ' 20 N ' is applied at the centre of the disc. If friction is sufficient enough to avoid slipping then the frictional force acting between the plank and the disc will be:


 

Option: 1

1 N


Option: 2

3 N


Option: 3

5 N


Option: 4

7 N


Answers (1)

best_answer

acceleration of the point of contact.

=\left(\frac{F-f}{m}\right)-r\left(\frac{r f}{\frac{1}{2} m r^2}\right)

=\frac{F-3 f}{m}

To avoid slipping, acceleration of the plank should be same

a=\frac{f}{m} \\

\frac{F-3 f}{m}=\frac{f}{m} \\

f=\frac{F}{4}=5 \mathrm{~N}

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